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### Grade 8 - Mathematics3.25 Area of Quadrilateral

 Example: The length of diagonal is 10 cm. and the heights of perpendicular sides are 6 cm. and 7 cm. respectively. Find the area of quadrilateral. Solution: The area of the quadrilateral = 1/2 * d(h1+h2) Given that, d = 10cm., h1 = 6cm. and h2 = 7 cm. A = 1/2 * 10(6+7) A = 5 (13) A = 65 Sq.cm. Directions: Solve the following problems. Also write at least ten examples of your own.
 Q 1: The length of diagonal is 18 cm. and the heights of perpendicular sides are 5.6 cm. and 9.4 cm. respectively. Find the area of quadrilateral.135.75 Sq.cm.135 Sq.cm.135.25 Sq.cm.135.5 Sq.cm. Q 2: The length of diagonal is 20 cm. and the heights of perpendicular sides are 7.6 cm. and 9.4 cm. respectively. Find the area of quadrilateral.170.5 Sq.cm.170 Sq.cm.170.25 Sq.cm.170.75 Sq.cm. Q 3: The length of diagonal is 8 cm. and the heights of perpendicular sides are 7.4 cm. and 9.7 cm. respectively. Find the area of quadrilateral.68.4 Sq.cm.68.46 Sq.cm.68.6 Sq.cm.68.8 Sq.cm. Q 4: The length of diagonal is 23 cm. and the heights of perpendicular sides are 7.8 cm. and 9.5 cm. respectively. Find the area of quadrilateral.198.45 Sq.cm.198.95 Sq.cm.198.75 Sq.cm.198.65 Sq.cm. Q 5: The length of diagonal is 15 cm. and the heights of perpendicular sides are 7.5 cm. and 4.6 cm. respectively. Find the area of quadrilateral.90.25 Sq.cm.90 Sq.cm.90.75 Sq.cm.90.5 Sq.cm. Q 6: The length of diagonal is 19 cm. and the heights of perpendicular sides are 7.6 cm. and 5.8 cm. respectively. Find the area of quadrilateral.127.9 Sq.cm.127.5 Sq.cm.127.3 Sq.cm.127.7 Sq.cm. Q 7: The length of diagonal is 25 cm. and the heights of perpendicular sides are 15.6 cm. and 9.4 cm. respectively. Find the area of quadrilateral.312.25 Sq.cm.312 Sq.cm.312.75 Sq.cm.312.5 Sq.cm. Q 8: The length of diagonal is 16 cm. and the heights of perpendicular sides are 8.6 cm. and 10.9 cm. respectively. Find the area of quadrilateral.156.5 Sq.cm.156 Sq.cm.156.25 Sq.cm.156.75 Sq.cm. Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!

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