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### Grade 8 - Mathematics3.37 Area of a Sector - I

 Example: The radius of a circle is 21cm. An arc AB subtends an angle of 105° at the center O. Find that area of the sector OAB. Solution: The area of the sector = x/360 * p r2 Given that, r = 21 cm., x = 105°. A = 105/360 * 22/7 * 21 * 21 A = 105/40 * 22 * 7 A = 16170/40 A = 404.25 Sq. cm. Directions: Solve the following problems and correct the answer at two decimal place. Also write at least ten examples of your own.
 Q 1: The radius of a circle is 2.1 cm. An arc AB subtends an angle of 80° at the center O. Find that area of the sector OAB.None of these2.08 sq.cm.4.08 sq.cm.3.08 sq.cm. Q 2: The radius of a circle is 8.4 cm. An arc AB subtends an angle of 120° at the center O. Find that area of the sector OAB.74.92 sq.cm.73.92 sq.cm.72.92 sq.cm.71.92 sq.cm. Q 3: The radius of a circle is 7.7 cm. An arc AB subtends an angle of 140° at the center O. Find that area of the sector OAB.73.47 sq.cm.71.47 sq.cm.74.47 sq.cm.72.47 sq.cm. Q 4: The radius of a circle is 35 cm. An arc AB subtends an angle of 130° at the center O. Find that area of the sector OAB.1391.28 sq.cm.1390.28 sq.cm.1392.28 sq.cm.1389.28 sq.cm. Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!