
Example: The height of a tent is 10 cm. Its base diameter is 48 cm. What is its slant height? Solution: Height of a tent (h) = 10cm. Its base radius (r) = diameter/2 = 48/2 = 24cm. l^{2} = h^{2} + r^{2} l^{2} = 10^{2} + 24^{2} l^{2} = 100 + 576 l^{2} = 676 l = Ö676 l = 26cm. Therefore, the slant height is 26cm. Directions: Solve the following problems. Also write at least 10 examples of your own. 