High School Mathematics 4.15 Word Problems on Cone - I

Directions: Solve the following problems. Also write at least 5 examples of your own.

Q 1: The ratio of base radius and height of a cone is 3:4. If the cost of smoothing the curved surface area at 6 cents per 1 Sq.cm. is $ 34.65. The find volume of liquid containing in it. (in liters) (1 liter = 1000 cu. cm.) 1.62 liters 0.162 liters 162 liters 16.2 liters

Q 2: The ratio of base radius and height of a cone is 3:4. If the cost of smoothing the curved surface area at 5 cents per 1 Sq.cm. is $ 115.50. The find volume of liquid containing in it. (in liters) (1 liter = 1000 cu. cm.) 12.369 liters 12.936 liters 12.639 liters 129.36 liters

Q 3: The ratio of base radius and height of a cone is 3:4. If the cost of smoothing the curved surface area at 2 cents per 1 Sq.cm. is $ 103.95. The find volume of liquid containing in it. (in liters) (1 liter = 1000 cu. cm.) 43.695 liters 43.569 liters 43.965 liters 43.659 liters

Q 4: The ratio of base radius and height of a cone is 3:4. If the cost of smoothing the curved surface area at 2 cents per 1 Sq.cm. is $ 2598.75. The find volume of liquid containing in it. (in liters) (1 liter = 1000 cu. cm.) 547.735 liters 547.375 liters 5457.375 liters 547.7375 liters

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