Email us to get an instant 20% discount on highly effective K-12 Math & English kwizNET Programs!

#### Online Quiz (WorksheetABCD)

Questions Per Quiz = 2 4 6 8 10

### High School Mathematics - 210.18 Trignometry Review

 Function 0o 30° 45° 60° 90° sin Ö0/2 Ö1/2 Ö2/2 Ö3/2 Ö4/2 cos Ö4/2 Ö3/2 Ö2/2 Ö1/2 0 tan 0 Ö3/3 1 Ö3 undefined sec 1 2Ö3/3 Ö2 2 undefined csc undefined 2 Ö2 2Ö3/3 1 cot undefined Ö3 1 Ö3/3 0

 sin cos tan 0 0 1 0 90 1 0 infinity 180 0 -1 0 270 -1 0 infinity

Functions of angles in all quadrants in terms of those in quadrant 1
 -A 900 ± A P/2 ± A 1800 ± A P ± A 2700 ± A 3P/2 ± A 3600 ± A 2P ± A sin -sinA cos A ±sin A -cosA ±sin A cos cos A ±sin A -cos A ±sin A cos A tan -tan A ±cot A ± tan A ±cot A ±tan A csc -csc A sec A ± csc A -sec A ±csc A sec sec A ± csc A -sec A ±csc A sec A cot -cot A ± tan A ± cot A ±tan A ± cot A

 Q 1: What is the angle of elevation of the sun when the length of the shadow of a pole is 31/2 times the height of the pole?30o90o60o Q 2: If the shadow of a tower is 30 metres, when the sun's altitude is 30o, what is the length of the shadow when the sun's altitude is 60o?Answer: Q 3: The horizontal distance between two towers is 60 metres and the angular depression of the top of the first as seen from the top of the second, which is 150 metres is 30o. Find the height of the first.115.36 metres100 metres120 metres Q 4: If in two circlesarcs of the same length subtend angles 60o and 75o at the centre, find the ratio of their radii.5:42:31:2 Q 5: Find the degree measure of the angle subtended at the centre of a circle of diamter 200 cm by an arc of length 22cm.33o12o36l45o Q 6: In triangle ABC, a = 8.4 cm, b = 7.6 cm and c = 9.2 cm. Calculate the area of triangle ABC.30 sq cm45 sq cm50 sq. cm Q 7: Find the degree measure of 3/4.45o35o42057l18ll Q 8: Solve the triangle ABC given that A = 67o, b = 3 cms, c = 2 cms.a = 5 cm, B = 70o19l, C = 39o 41la = 2.88 cm, B = 73o19l, C = 39o 41la = 2 cm, B = 73oC = 39o 41l Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!