|Theorem: The ratio of the areas of similar triangles is equal to the ratio of the squares of their corresponding sides.|
Given: Triangle ABC and Triangle PQR are similar
Example: Prove that PM2 = QM x MR
Solution: As PM is perpendicular to QR we find that triangles PMQ and PMR are similar
Hence PM/MR = QM/PM (In similar triangles corresponding sides are proportional)
Hence PM2 = MR x QM
Directions: Solve the following problems. Also write at least 10 examples of your own.