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### Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation8.15 Percentage Word Problems - 2

 Example 1: Ria bought a dress with a price tag of \$24. She paid only \$6. What percent discount did she get? The actual discount she received = \$24 - \$6 = \$18 This discount was on the regular price of \$24. Therefore, percent discount = (18/24) x 100 = 75% Example 2: John paid \$9 for a book after a discount of 75%. What was the original price? He paid \$9 for the book after 75% discount. That means he paid 25% of the original price. If 25% is \$9, how much is 100%? Therefore, Original Price = (100/25) x 9 = \$36 Directions: Answer the following qustions. Also write at least ten story problem examples of your own.
 Q 1: Mr. Williamson, a parts inspector, rejected 21 parts from a total of 420 parts. Of the parts inspected, what percent was accepted? (Hint: Divide 399/420 and then convert the decimal to percent)55%75%95% Q 2: If Greg got 85% of the answers correct in his math test, what percent did he have incorrect?15%20%5% Q 3: At a store, a dress sold for \$56. This represented 80% of the original price. What was the original price?\$50\$35\$70 Q 4: Cathy bought for \$75 a coat which usually sells for \$125. What percent of the original price did she pay? (Hint: Divide 75/125 and then convert the decimal to percent)60%40%50% Q 5: Sue is reading a book that has 300 pages. She has already read 200 pages. What percent of the book is left for her to read?33 1/3 %23 1/3 %50 % Q 6: The price of a new car is \$14,450. Mr. Smith made a down payment of 15% when he purchased the car. How much did he pay?\$2267.50\$4167.60\$2167.50 Q 7: Jill bought a dress for \$38.80 that was originally priced at \$48.50. By what percent was the dress reduced from the original price? (Hint: Subtract the two prices and then divide with the original price)25%20%30% Q 8: A worker paid a tax of 18.6% on \$912.24 of his income. How much money did he pay?\$160.20\$169.68\$140.68 Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!