Direct Variation or Direct Proportion - Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation - kwizNET Math/Science/English Homeschool/Afterschool/Tutoring Lessons/Worksheets/Quizzes/Trivia

Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation 7.9 Direct Variation or Direct Proportion

Directions: Answer the following questions. Also write at least ten examples of your own.

Q 1: A family spends 120 dollars per month for vegetables when the cost of vegetables is 5 dollars per kg. How much amount must the family spend per month, if the cost of vegetables goes up to 5.75 dollars per kg? 130 dollars 138 dollars 140 dollars

Q 2: The numbers r and s vary directly and the constant of variation is 3/5. Find r if s=45; and find s if r =33. 50 and 25 respectively 27 and 55 respectively 55 and 27 respectively

Q 3: The amount of heat (H) produced in human body by burning of proteins is directly proportional to the amount of proteins (A) burnt. If burning of 1 gram of proteins produces 32 calories of heat, how much proteins should be burnt to produce 52 calories? 20 grams 15 grams 13 grams

Q 4: One evening the length of the shadow of a building's pillar of height 28 m is 42 m. What will be the length of the shadow of the building's tower of height 36 m at that time? 45 m 50 m 54 m

Q 5: The numbers x and y are directly proportional and x=9 when y=3. Find x when y=8; and find y when x=42. 14 and 24 respectively 25 and 15 respectively 24 and 14 respectively

Q 6: The expenditure per month for 15 students in a dormitory is $2,250. If 10 more students joined, what will be the monthly expenditure now? $3,750 $2,750 $3,500

Q 7: A motor bike travels 225 km with 5 liters of gas. How many liters of gas are needed to travel 135 km? 3.5 liters 3 liters 4 liters

Q 8: The weight E of a man on earth's surface is directly proportional to his weight M on mars. The constant of proportionality is 3, if a man weights 126 kg on earth, how much will he weigh on mars? 45 kgs 42 kgs 40 kgs

Question 9: This question is available to subscribers only!

Question 10: This question is available to subscribers only!