Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation 1.18 Linear Equations - 2
Examples:
2x + 8 = 14 Then x = ?
2x + 8 = 14 subtracting 8 from both sides
2x + 8 - 8 = 14 - 8
2x = 6 Dividing both sides by 2
2x/2 = 6/2
x = 3
6y - 15 = 2y + 9 Then y = ?
6y - 15 = 2y + 9 subtracting 2y from both sides
6y - 15 - 2y = 2y + 9 - 2y
4y - 15 = 9 Adding 15 both sides
4y - 15 + 15 = 9 + 15
4y = 24 dividing both sides by 4
4y/4 = 24/4
y = 6
4(s + 1) = -2(4 - s) distributive property Note: Negative number multiplied by a negative number is positive. -2 x -s = 2s
4s + 4 = -8 + 2s subtracting 2s both sides
4s + 4 - 2s= -8 + 2s - 2s
2s + 4 = -8 subtracting 4 both sides
2s + 4 - 4 = -8 - 4
2s = - 12 dividing both sides by 2
2s/2 = - 12/2
s = -6
2/x = 3/6
x/2 = 6/3
x/2 = 2
x = 4
t/6 + 2 = t/3
This equation contains fractions so multiply both sides by the LCD of 6 and 3 that is 6
6(t/6 + 2) = 6(t/3)
t + 12 = 2t subtracting t from both sides
t + 12 - t = 2t - t
12 = t
Therefore, t = 12
Directions: Solve for the variables. Also write at least 10 examples of your own.