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### Grade 7 - Mathematics6.26 Equations With Decimal Coefficients - II

 Example: Solve the equation (0.6)x + 0.02 = x - 1.78. Solution: Writing decimals as common fractions, we have 6x/10 + 2/100 = x - 178/100 L.C.M. of denominators 10 and 100 is 100. \ Multiplying both sides of the equation by 100 60x + 2 = 100x - 178 Transposing 100x to L.H.S. and 2 to R.H.S. we have 60x - 100x = -178 - 2 -40x = -180. Dividing both sides by -40 we get -40x/-40 = -180/-40 x = 9/2 = 4.5 Verifications: Substituting x = 4.5 in the equation we get L.H.S. Þ (0.6)x + 0.02 = (0.6)(4.5) + 0.02 = 2.70 R.H.S. Þ x - 1.78 = 4.5 - 1.78 = 2.72 \ L.H.S. = R.H.S. \ x = 4.5 is the solution. Directions: Solve the following problems. Also write at least five equations with decimal coefficients of your own and solve them.
 Q 1: Solve the equation (3.6)x - 1.02 = 2x + 3.2.211/80112/788086/112 Q 2: Solve the equation (2.4)x - 5.2 = 3x + 4.2.43/1247/319/1417/9 Q 3: Solve the equation (2.1)x - 2.2 = x - 5.2.15/8-30/11-30/192/14 Q 4: Solve the equation (1.2)x + 2.1 = 9x - 2.2.43/7816/1743/3578/45 Q 5: Solve the equation (3.1)x + 5.2 = 4x + 3.1.15/13-7/37/316/13 Q 6: Solve the equation (2.6)x - 0.02 = 3x - 5.6.14.913.9513.5 Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!