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 Example: Find the additive inverse B of A, where A = 3x2+7x+2. Solution: To obtain the additive inverse B of A, write the additive inverses of each of the coefficients of its terms. That is -3, -7, -2, are the coefficients of the terms in the polynomial B respectively. Therefore, B = -3x2-7x-2. Verification: A+B = (3x2+7x+2)+(-3x2-7x-2) = (3x2-3x2)+(7x-7x)+(2-2) = (3-3)x2+(7-7)x+(2-2) = 0.x2+0.x+x = 0 Directions: Solve the following problems. Also write at least ten examples of your own.
 Q 1: Find the additive inverse of (7x2+3x+3).-7x2-3x-37x2+3x-3-7x2+3x+3-7x2+3x-3 Q 2: Find the additive inverse of (9x2-3x-9).-9x2+3x+99x2-3x+9-9x2-3x-9-9x2-3x+9 Q 3: Find the additive inverse of (7x3-9x+3).-7x3+9x-3-7x3-9x-37x3+9x-37x3-9x-3 Q 4: Find the additive inverse of (-3x2-7x+2).-3x2+7x-2-3x2-7x-23x2+7x-23x2-7x-2 Q 5: Find the additive inverse of (6x2-3x+3).6x2-3x-3-6x2-3x-3-6x2+3x-36x2+3x-3 Q 6: Find the additive inverse of (9x3-7x+3).-9x3-7x-39x3-7x-39x3+7x-3-9x3+7x-3 Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!