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### Grade 7 - Mathematics4.6 Factorization - II

 Example: Express 9a2 + 15ab as product of factors. Solution: To find factors first we find HCF of the terms, that is Breaking each monomial simplest numerical literal factors, we get 9a2 = 3 * 3 * a * a 15ab = 3 * 5 * a * b HCF of the terms = 3 * a = 3a 9a2 + 15ab = 3a * 3a + 3a * 5b (Since 3a is the HCF) = 3a(3a + 5b) Directions: Write the given terms as product of factors. Also write at least 10 examples of your own.
 Q 1: Express 21a2 + 27ab as product of factors.3a(7a+9b)9a(7a+3b)7a(3a+9b) Q 2: Express 18x2 + 9xy as product of factors.9x(2x+y)x(9x+2y)2x(9x+y) Q 3: Express 24x2 + 72xy as product of factors.x(24x+3y)24x(x+3y)3x(24x+y) Q 4: Express 24x2 + 42xy as product of factors.7x(4x+6y)4x(7x+6y)6x(4x+7y) Q 5: Express 128x2 + 96xy as product of factors.4x(32x+3y)32x(4x+3y)3x(32x+4y) Q 6: Express 30x2 + 45xy as product of factors.15x(2x+3y)2x(15x+3y)3x(2x+15y) Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!