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### Grade 7 - Mathematics4.3 Common Binomial Factor - II

 Example: Factorise (6a-b)(x+y) - (2a-3b)(x+y). Solution: Give that (6a-b)(x+y) - (2a-3b)(x+y) = [(6a-b)-(2a-3b)](x+y)  {Since (x+y) is the greatest common factor} = [6a-b-2a+3b](x+y) = [4a+2b](x+y) = 2[2a+b](x+y) Directions: Solve the following problems. Also write at least ten examples of your own.
 Q 1: Factorise (9x+2y)(3a+5b) + (7x+3y)(3a+5b).(-16x+5y)(3a+5b)(16x-5y)(3a+5b)(16x+5y)(3a+5b) Q 2: Factorise (4a-b)(3a+2y) - (7a+b)(3a+2y).(-3a-2b)(3a+2y)(3a-2b)(3a+2y)(3a)(3a+2y) Q 3: Factorise (3x-2y)(3a+b) - (4x-3y)(3a+b).(x-y)(3a+b)(x+y)(3a+b)(-x+y)(3a+b) Q 4: Factorise (6a-3b)(2x+3y) - (6a+3b)(2x+3y).(2a-6b)(2x+3y)(-6b)(2x+3y)(6b)(2x+3y) Question 5: This question is available to subscribers only! Question 6: This question is available to subscribers only!

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