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Grade 7 - Mathematics
4.19 Find The Factors of Difference of Two Squares - IV

Example: Factorise 2a3 - 32ab2.
Solution: Given that 2a3 - 32ab2
= 2a.a2 - 2a.16b2
= 2a (a2 - 16b2)
= 2a [(a+4b) (a-4b)]
= 2a (a+4b) (a-4b)
Directions: Find the factors of the given expressions and show your work. Also write at least ten examples of your own.
Q 1: Factorise 3x2 - 27.
3(x-3)(x-3)
3(x+3)(x+3)
3(x+3)(x-3)

 Q 2: Factorise a5 - a3.
a3(a-1)(a-1)
a3(a+1)(a-1)
a3(a+1)(a+1)

Q 3: Factorise 2a2 - 98.
2(x+7)(x+7)
2(x+7)(x-7)
2(x-7)(x-7)

 Q 4: Factorise 2a9 - 32a.
2a(a4+4)(a2-2)(a2-2)
2a(a4+4)(a2+2)(a2+2)
2a(a4+4)(a2+2)(a2-2)

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 Question 6: This question is available to subscribers only!


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