Name: ___________________

Date:___________________

kwizNET Subscribers, please login to turn off the Ads!
Email us to get an instant 20% discount on highly effective K-12 Math & English kwizNET Programs!

Middle/High School Algebra, Geometry, and Statistics (AGS)
2.11 Solving Inequations - I

Example: Solve 3x + 2 < 10.
Solution: Given that 3x + 2 < 10
Adding -2 to both sides.
3x + 2 - 2 < 10 - 2
3x < 8
Dividing both sides by 3, we get
3x/3 < 8/3
x < 8/3
\ Any number < 8/3 is a solution.

Verification: Substituting x = 1 < 8/3 in the equation, we get
L.H.S. = 3x + 2 = 3 * 1 + 2 = 3 + 2 = 5 < 10 = R.H.S.
\ 1 < 8/3 is a root.
Similarly we can show that any number less than 8/3 is a root.


Directions: Solve the following inequality. Also write at least ten examples of your own.
Q 1: Solve 6x + 3 < 10.
x > 7/6
x > 6/7
x < 7/6
x < 6/7

Q 2: Solve 9x + 2 < 15.
x >9/13
x > 13/9
x < 13/9
x < 9/13

Q 3: Solve 7x - 9 < 3.
x > 12/7
x > 7/12
x < 12/7
x < 7/12

Q 4: Solve 6x - 9 < 5.
x < 7/3
x < 3/7
x > 3/7
x > 7/3

Q 5: Solve 4x - 8 < 3.
x > 4/11
x < 4/11
x < 11/4
x > 11/4

Q 6: Solve 15x - 10 < 5.
x < 1
x > 1
x < -1
None of these

Question 7: This question is available to subscribers only!

Question 8: This question is available to subscribers only!


Subscription to kwizNET Learning System costs less than $1 per month & offers the following benefits:

  • Unrestricted access to grade appropriate lessons, quizzes, & printable worksheets
  • Instant scoring of online quizzes
  • Progress tracking and award certificates to keep your student motivated
  • Unlimited practice with auto-generated 'WIZ MATH' quizzes
  • Child-friendly website with no advertisements


© 2003-2007 kwizNET Learning System LLC. All rights reserved. This material may not be reproduced, displayed, modified or distributed without the express prior written permission of the copyright holder. For permission, contact info@kwizNET.com
For unlimited printable worksheets & more, go to http://www.kwizNET.com.