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### Geometry4.12 Area of a Trapezoid - II

 Example: The lengths of the parallel sides of a trapezoid are 9 cm and 7cm. Its area is 18 sq cm. Find the distance between the parallel lines. Solution: The area of a trapezoid is (A ) =1/2 * (a+b) * h. Given that, a = 9 cm, b = 7 cm and A = 18 sq cm. h = 2A/(a+b) h = (2*18)/(9+7) h = 36/16 h = 2.25 cm. \ The distance between the parallel lines = 2.25 cm. Directions: Read the above example carefully and answer the following questions. Also write at least 10 examples of your own.
 Q 1: The lengths of the parallel sides of a trapezoid are 17 cm and 15 cm. Its area is 192 sq cm. Find the distance between the parallel lines.12 cm25 cm15 cm18 cm Q 2: The lengths of the parallel sides of a trapezoid are a cm and b cm. Its area is (ac + bc)/2 sq cm. Find the distance between the parallel lines.ac cmc cma cmb cm Q 3: The lengths of the parallel sides of a trapezoid are 15.25 cm and 13.75 cm. Its area is 188.50 sq cm. Find the distance between the parallel lines.14 cm12.5 cm13 cm13.5 cm Q 4: The lengths of the parallel sides of a trapezoid are 9 cm and 7 cm. Its area is 20 sq cm. Find the distance between the parallel lines.4.5 cm3.5 cm2.5 cm25 cm Q 5: The lengths of the parallel sides of a trapezoid are 12x cm and 14x cm. Its area is 130x2 sq cm. Find the distance between the parallel lines.4.5x cm10x cm5.5x cm6x cm Q 6: The lengths of the parallel sides of a trapezoid are 18cm and 16cm. The distance between the parallel lines is given by 6 cm. Find its area.102 sq cm185 sq cm125 sq cm200 sq cm Question 7: This question is available to subscribers only! Question 8: This question is available to subscribers only!